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Sunday, March 31, 2019

minat logaritma

a) 4log 8 + 27log 9
= 22log 23 + 33log 32
= 3/2 2log 2 + 2/3 3log 3
= 3/2 + 2/3 = 9/6 + 4/6 = 13/6
b) 8log 4 + 27log 1/9
23log 22 + 33log 3−2
= 2/3 2log 2 + (−2/3) 3log 3
= 2/3 − 2/3 = 0
2.
a) √2log 8
= 21/2log 23 = 3/0,5 2log 2 = 3/0,5 = 6
b) √3log 9
= 31/2log 32 = 2/0,5 3log 3 = 2/0,5 = 4
3.
log p3 q2 = log p3 + log q2 = 3 log p + 2 log q = 3A + 2B
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